x^2=+103x+17

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Solution for x^2=+103x+17 equation:



x^2=+103x+17
We move all terms to the left:
x^2-(+103x+17)=0
We add all the numbers together, and all the variables
x^2-(103x+17)=0
We get rid of parentheses
x^2-103x-17=0
a = 1; b = -103; c = -17;
Δ = b2-4ac
Δ = -1032-4·1·(-17)
Δ = 10677
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-103)-\sqrt{10677}}{2*1}=\frac{103-\sqrt{10677}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-103)+\sqrt{10677}}{2*1}=\frac{103+\sqrt{10677}}{2} $

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